šŸ’” Light — Reflection and Refraction — Class 10

Laws of reflection, spherical mirrors, refraction, Snell's law, lenses, and sign convention

1. Reflection of Light

šŸ“– Laws of Reflection

Law 1: The angle of incidence (∠i) equals the angle of reflection (∠r).

Law 2: The incident ray, reflected ray, and the normal at the point of incidence all lie in the same plane.

2. Spherical Mirrors

šŸ“– Key Terms

Concave mirror: Reflecting surface is on the inner (hollow) side. Converging mirror.

Convex mirror: Reflecting surface is on the outer (bulging) side. Diverging mirror.

Centre of curvature (C): Centre of the sphere of which mirror is a part.

Principal focus (F): Point where parallel rays converge after reflection (concave) or appear to diverge from (convex).

Focal length (f): Distance from mirror to focus. f = R/2 (where R = radius of curvature)

Principal axis: Line joining the pole to the centre of curvature.

2.1 Image Formation by Concave Mirror

Object PositionImage PositionNature of Image
At infinityAt FReal, inverted, highly diminished (point)
Beyond CBetween F and CReal, inverted, diminished
At CAt CReal, inverted, same size
Between C and FBeyond CReal, inverted, magnified
At FAt infinityReal, inverted, highly magnified
Between F and poleBehind mirrorVirtual, erect, magnified

2.2 Image Formation by Convex Mirror

⚔ Convex Mirror

Always forms a virtual, erect, and diminished image behind the mirror, regardless of object position.

Used as: Rear-view mirrors in vehicles (gives wider field of view), security mirrors in shops.

2.3 Mirror Formula and Magnification

šŸ“– Sign Convention (New Cartesian)

• All distances measured from pole (P) along principal axis

• Distances in direction of incident light (+ve direction = left to right)

• Object is always on left → object distance (u) is always negative

• Real image: v is negative (same side as object)  |  Virtual image: v is positive (behind mirror)

šŸ“– Formulas

Mirror Formula: 1/v + 1/u = 1/f

Magnification: m = –v/u = h'/h

m > 0: virtual, erect image  |  m < 0: real, inverted image

|m| > 1: magnified  |  |m| < 1: diminished  |  |m| = 1: same size

šŸ’” Example: Mirror Problem

Q: An object is placed 10 cm in front of a concave mirror with focal length 15 cm. Find image position.

u = –10 cm (object on left), f = –15 cm (concave mirror)

1/v = 1/f – 1/u = 1/(–15) – 1/(–10) = –1/15 + 1/10

= (–2 + 3)/30 = 1/30 → v = +30 cm

Image is 30 cm behind mirror — virtual, erect, magnified

m = –v/u = –(30)/(–10) = +3 (magnified 3Ɨ, erect)

3. Refraction of Light

šŸ“– Refraction

Refraction is the bending of light when it passes from one medium to another (different optical densities).

Cause: Change in speed of light in different media

šŸ“– Snell's Law (Laws of Refraction)

Law 1: The incident ray, refracted ray, and normal at the point of incidence are all in the same plane.

Law 2 (Snell's Law): n₁ sin i = nā‚‚ sin r

Or: sin i / sin r = nā‚‚/n₁ = constant (for given pair of media)

šŸ“– Refractive Index

n = speed of light in vacuum (c) / speed of light in medium (v)

n = c/v    (n is always ≄ 1)

Higher n = optically denser = light bends more toward normal

n for water ā‰ˆ 1.33  |  n for glass ā‰ˆ 1.5  |  n for diamond = 2.42

4. Spherical Lenses

4.1 Convex and Concave Lenses

šŸ“– Types of Lenses

Convex lens (converging): Thicker at centre, converges light. f is positive.

Concave lens (diverging): Thinner at centre, diverges light. f is negative.

4.2 Image Formation by Convex Lens

Object PositionImage PositionNature
At infinityAt Fā‚‚Real, inverted, point-sized
Beyond 2F₁Between Fā‚‚ and 2Fā‚‚Real, inverted, diminished
At 2F₁At 2Fā‚‚Real, inverted, same size
Between F₁ and 2F₁Beyond 2Fā‚‚Real, inverted, magnified
At F₁At infinityReal, inverted, highly magnified
Between F₁ and lensSame side as objectVirtual, erect, magnified

šŸ“– Lens Formula and Power

Lens Formula: 1/v – 1/u = 1/f

Magnification: m = v/u

Power of lens: P = 1/f (in metres)

Unit of power: Dioptre (D)  |  Convex lens: P positive  |  Concave: P negative

Combined lenses: P = P₁ + Pā‚‚ + Pā‚ƒ ...

šŸ’” Example: Lens Problem

Q: An object is placed 15 cm from a convex lens of focal length 10 cm. Find image position and nature.

u = –15 cm, f = +10 cm

1/v = 1/f + 1/u = 1/10 + 1/(–15) = 1/10 – 1/15 = (3–2)/30 = 1/30

v = +30 cm (positive: real image, opposite side)

m = v/u = 30/(–15) = –2 (inverted, magnified 2Ɨ)

Image: Real, inverted, magnified, 30 cm on other side of lens

šŸ“‹ Formula Sheet — Light

Mirror

1/v + 1/u = 1/f

f = R/2

m = –v/u

Refraction (Snell's Law)

n₁ sin i = nā‚‚ sin r

n = c/v

Lens

1/v – 1/u = 1/f

m = v/u

P = 1/f (D)