Complete notes with graphical methods, examples, and formula sheet
Linear equations are algebraic expressions that represent straight lines when plotted on a graph. They are fundamental in mathematics and have numerous real-world applications in science, economics, and engineering.
A linear equation in two variables is an equation that can be written in the form:
ax + by + c = 0
Where a, b, and c are real numbers, and a and b are not both zero. The variables are x and y.
Examples: 2x + 3y = 6, x - y = 5, 3x + 4y - 12 = 0
Q: Which of the following are linear equations in two variables?
a) 2x + 3y = 5
b) x² + y = 4
c) 3x - 2y + 7 = 0
d) xy + 5 = 0
e) y = 2x - 3
Solution:
a) â Linear (can be written as 2x + 3y - 5 = 0)
b) â Not linear (x² means power is 2, not 1)
c) â Linear (already in standard form)
d) â Not linear (xy means product of variables)
e) â Linear (can be written as 2x - y - 3 = 0)
Linear equations have:
âĸ Variables with power 1 only (x, y, not x², y², âx, etc.)
âĸ No products of variables (no xy, x²y, etc.)
âĸ Straight line graphs
Non-linear equations: Have higher powers, products, or other operations
A solution of a linear equation in two variables is a pair of values (x, y) that satisfies the equation.
A solution is an ordered pair (x, y) that makes the equation true when substituted.
For example, if (2, 3) is a solution of 2x + y = 7, then:
2(2) + 3 = 4 + 3 = 7 â (True, so it's a solution)
Q: Find three solutions of 2x + y = 6
Solution:
Method: Choose values for x, then find corresponding y values
When x = 0:
2(0) + y = 6
y = 6
Solution: (0, 6)
When x = 1:
2(1) + y = 6
2 + y = 6
y = 4
Solution: (1, 4)
When x = 3:
2(3) + y = 6
6 + y = 6
y = 0
Solution: (3, 0)
Three solutions: (0, 6), (1, 4), (3, 0)
The graph of a linear equation in two variables is always a straight line. Every point on the line represents a solution of the equation.
Q: Draw the graph of x + y = 5
Solution:
Step 1: Find three solutions
When x = 0: y = 5 â Point (0, 5)
When x = 2: y = 3 â Point (2, 3)
When x = 5: y = 0 â Point (5, 0)
Step 2: Make a table
x | 0 | 2 | 5
y | 5 | 3 | 0
Step 3: Plot points (0,5), (2,3), (5,0) on graph
Step 4: Join them with a straight line
Result: A straight line passing through these points represents x + y = 5
âĸ Always choose simple values for x (like 0, 1, 2, -1, etc.) to make calculations easier.
âĸ Use graph paper for accuracy.
âĸ Choose an appropriate scale based on the values.
âĸ Label the axes and mark the scale clearly.
âĸ Use a ruler to draw the line - it must be straight!
Some special linear equations represent lines parallel to the coordinate axes.
| Feature | Parallel to X-axis | Parallel to Y-axis |
|---|---|---|
| Equation | y = k | x = k |
| Direction | Horizontal | Vertical |
| Variable Constant | y is constant | x is constant |
| Example | y = 5 | x = 3 |
| Points | (..., 5), any x with y=5 | (3, ...), any y with x=3 |
Q1: Draw the graph of y = 4
Solution:
y = 4 means y-coordinate is always 4
Points: (-2, 4), (0, 4), (1, 4), (3, 4)
This is a horizontal line parallel to X-axis, 4 units above it.
Q2: Draw the graph of x = -2
Solution:
x = -2 means x-coordinate is always -2
Points: (-2, 0), (-2, 1), (-2, -3), (-2, 5)
This is a vertical line parallel to Y-axis, 2 units to the left of it.
If a graph is given, we can find its equation by identifying two or more points on the line.
Q: Find the equation of a line passing through (1, 2) and (3, 4)
Solution:
Using two-point form, we can see both points satisfy certain patterns.
Let's check if they satisfy y = mx + c
From (1, 2): 2 = m(1) + c â 2 = m + c ... (i)
From (3, 4): 4 = m(3) + c â 4 = 3m + c ... (ii)
Subtracting (i) from (ii):
4 - 2 = 3m + c - (m + c)
2 = 2m
m = 1
Substituting m = 1 in (i):
2 = 1 + c
c = 1
Equation: y = x + 1 or x - y + 1 = 0
Problem: A taxi charges âš20 as fixed charge and âš10 per km. Write an equation for total fare.
Solution:
Let x = distance in km
Let y = total fare in âš
Total fare = Fixed charge + Variable charge
y = 20 + 10x
Equation: y = 10x + 20 or 10x - y + 20 = 0
Using the equation:
For 5 km: y = 10(5) + 20 = 50 + 20 = âš70
For 10 km: y = 10(10) + 20 = 100 + 20 = âš120
Problem: The sum of two numbers is 15. Express this as a linear equation and find three solutions.
Solution:
Let the two numbers be x and y
Given: Sum = 15
Equation: x + y = 15
Finding three solutions:
When x = 0: y = 15 â Solution (0, 15)
When x = 5: y = 10 â Solution (5, 10)
When x = 10: y = 5 â Solution (10, 5)
Three solutions: (0, 15), (5, 10), (10, 5)
Interpretation:
(0, 15) means first number is 0, second is 15
(5, 10) means first number is 5, second is 10
(10, 5) means first number is 10, second is 5
ax + by + c = 0
Where a, b, c are real numbers
a and b cannot both be zero
Graph is always a straight line
General: ax + by = c
Slope-intercept: y = mx + c
Point-slope: y-yâ = m(x-xâ)
Intercept: x/a + y/b = 1
All forms are equivalent
1. Choose value for x
2. Substitute in equation
3. Solve for y
4. Write as ordered pair (x, y)
Infinite solutions exist!
1. Find 3 solutions (points)
2. Draw coordinate axes
3. Plot the points
4. Join with straight line
Use ruler for accuracy
Parallel to X-axis:
y = k (horizontal)
Parallel to Y-axis:
x = k (vertical)
k is constant distance
X-axis: y = 0
Y-axis: x = 0
Origin: (0, 0)
Special lines through origin
To check if (a, b) is solution:
Substitute x=a and y=b
If equation true â Solution â
If equation false â Not solution â
âĸ Infinitely many solutions
âĸ Graph is straight line
âĸ 2 points determine a line
âĸ All points on line = solutions
Remember: Linear = Straight!
âĸ Always verify your solutions by substituting back into the equation.
âĸ When graphing, choose simple values (0, 1, 2, -1) for easier calculations.
âĸ Three points are better than two for accuracy when drawing graphs.
âĸ Use graph paper for neat and accurate graphs.
âĸ Remember: The graph must be a STRAIGHT line - use a ruler!
âĸ For word problems, carefully identify what each variable represents.
âĸ Check if your answer makes sense in the context of the problem.
âĸ Practice different forms of equations - be comfortable converting between them.
1. Find 3 solutions: 3x + 2y = 12
2. Graph the equation: 2x - y = 4
3. What is the equation of a line parallel to X-axis at distance 7 units above it?
4. Check if (2, 5) is a solution of x + 2y = 12
5. A notebook costs âšx and a pen costs âšy. If total cost of 3 notebooks and 2 pens is âš50, write the equation.
Answers:
1. (0,6), (2,3), (4,0) [or any valid solutions]
2. Plot points like (0,-4), (2,0), (3,2) and join
3. y = 7
4. 2 + 2(5) = 2 + 10 = 12 â Yes, it's a solution!
5. 3x + 2y = 50